(2*22^(1/2))^2=x^2+(7^(1/2))^2

Solution for (2*22^(1/2))^2=x^2+(7^(1/2))^2 equation:

(2*22^(1/2))^2=x^2+(7^(1/2))^2

We move all terms to the left:

(2*22^(1/2))^2-(x^2+(7^(1/2))^2)=0

We add all the numbers together, and all the variables

-(x^2+(7^(+1/2))^2)+(2*22^(+1/2))^2=0

We calculate fractions


(-(x^2+7^2^2)/()+()/()=0


We calculate terms in parentheses: +(-(x^2+7^2^2)/()+()/(), so:

-(x^2+7^2^2)/()+()/(

We add all the numbers together, and all the variables

-(x^2+7^2^2)/()+1

We multiply all the terms by the denominator


-(x^2+7^2^2)+1*()

We add all the numbers together, and all the variables

-(x^2+7^2^2)

We get rid of parentheses

-x^2-7^2^2

We add all the numbers together, and all the variables

-1x^2-2401

Back to the equation:

+(-1x^2-2401)


We get rid of parentheses

-1x^2-2401=0

a = -1; b = 0; c = -2401;
Δ = b2-4ac
Δ = 02-4·(-1)·(-2401)
Δ = -9604
Delta is less than zero, so there is no solution for the equation